Basically, the sum of the first 100 natural numbers is equal to 5050.
Hence, the answer to this question is 20100.
And hence the sum of the first 50 natural numbers to be 1275.
Thus, the sum of whole numbers from 1 to 100 is 5050.
Sum of Even Numbers 1 to 100
Consequently, Sn = 50(50+1) = 50 x 51 = 2550.
Even numbers 1 to 100
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, 100.
Hence, the sum of all odd numbers between 0 and 100 is 2500 . Q.
Check it out! So, here's the question: Do you know what 1+2+3+4+5+6 all the way up to 365 equals? I'll tell you: 66,795.
Then, out of nowhere, a bunch of mathematicians try to tell you that the sum of all positive integers, that is, 1 + 2 + 3 + 4 + 5 + 6 +... and so on to infinity is equal to... -1/12.
So we get the sum of the numbers from 1 to 300 as 1+2+3 . . . . . . . . . +300 = 45150.
The sum of the first 60 integers is 1,830. Rather than starting at 1 and counting and adding up all of the integers to 60, we can use Gauss' formula.
123 + 4 - 5 + 67 - 89 = 100.
Here are the rules: use every digit in order - 123456789 - and insert as many addition and subtraction signs as you need so that the total is 100. Remember the order of operations!
The number series 1, 2, 3, 4, . . . . , 98, 99. Therefore, 4950 is the sum of positive integers upto 99...
The sum of integers from 1 to 500 can be calculated using formula, S = n(a + l)/2. Here, n = 500, a = 1, l = 500. ⇒ S = 500(1 + 500)/2 = 125250.
So, The sum of 1 to 30 is 465.
Answer: Now note the natural numbers, which are from 1-to 100. According to arithmetic progression, natural numbers can be written down as 1, 2, 3, 4, 5, 6, 7, and 8 to 100. Basically, the sum of the first 100 natural numbers is equal to 5050.
But mathematicians and physicists don't like the concept of “getting nowhere”. So, there are ways to define the sums of non-converging infinite series so that they do not lead to contradictions. The one that leads legitimately to the conclusion that 1 + 2 + 3 + 4 … = -1/12 is called Ramanujan summation.
If you add one to infinity, you still have infinity; you don't have a bigger number.
1.01 ^ 365 = 37.78 | 0.99 ^ 365 = 0.03 | The significance of giving that 1% extra effort everyday!
In the 1780s a provincial German schoolmaster gave his class the tedious assignment of summing the first 100 integers. The teacher's aim was to keep the kids quiet for half an hour, but one young pupil almost immediately produced an answer: 1 + 2 + 3 + ... + 98 + 99 + 100 = 5,050.
For every 365 days of the year you save pennies. Starting at 1p on day one and then each day you add on a penny to the previous day's amount e.g. Day 2 = 2p, Day 3 = 3p, Day 4 = 4p etc. etc.
We know that odd numbers always end with an odd digit such as 1, 3, 5, 7, and 9. Therefore, the smallest odd number in this range of 1 to 1000 is 1 and the largest odd number is 999. The algorithm used to list down the odd numbers is adding 2 to the previous odd number.
2n − 1 is clearly odd because (2n − 1) mod 2 = 1. So 2n − 1 is an arbitrary odd number by definition. But adding 2 results in 2n + 1 which is odd for the same reason. Hence, adding 2 to an arbitrary odd number results in another odd number, specifically the next consecutive odd number.
The list of odd numbers from 1 to 100 is: 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49, 51, 53, 55, 57, 59, 61, 63, 65, 67, 69, 71, 73, 75, 77, 79, 81, 83, 85, 87, 89, 91, 93, 95, 97, 99.