The sum of the exponents of the prime factors of 130 is 3.
The complete prime factorization of 130 is 2 multiplied by 5 multiplied by 13. Since all prime factors are used only once in this factorization, the exponents for each prime factor are understood to be 1. Therefore, we can express the prime factorization of 130 with exponents as follows: 130 = 2^1 * 5^1 * 13^1.
Prime factorization of 130 is 2 × 5 × 13.
Due to the superstitious significance of the numbers it contains, the palindromic prime 1000000000000066600000000000001 is known as Belphegor's Prime, named after Belphegor, one of the seven princes of Hell.
The number 12,345,678,910,987,654,321 is indeed prime. It consists of 20 digits and is really easy to remember: count to 10 and then count backward again until you get to 1. But it has been unclear whether other primes take the palindromic form of starting at 1, ascending to the number n and then descending again.
The sum of the exponents of the prime factors in the prime factorization of 196 is 4.
7 Rules for Exponents with Examples
No, 130 is not a prime number. The number 130 is divisible by 1, 2, 5, 10, 13, 26, 65, 130. For a number to be classified as a prime number, it should have exactly two factors. Since 130 has more than two factors, i.e. 1, 2, 5, 10, 13, 26, 65, 130, it is not a prime number.
The HCF of 130 and 208 is 26.
what is the smallest whole number that can be written two ways as a sum of two different perfect squares? i.e.11squared plus 3 squared is 121+ 9=130 and7 squared + 9squared=49 +81= 130.
Step by Step Solution:
The general form of adding exponents with the same base and exponents is an + an = 2an. Let us look at example to understand this better. For example: 43 + 43 = 2(43) = 2 × 4 × 4 × 4 = 128.
No, 196 is not a prime number.
The sum of exponents of prime factors in the primefactorisation of 1764 is (a) 3 (b) 4 (c) 5 (d) 6 Ans : Prime factors of 1764 , 1764=4×49×9=22×72×32 The sum of exponents of prime factor is 2+2+2=6.
For example, entering either 1,000,000,000,000 or 1.0e12 will tell you ' The 1,000,000,000,000th prime is 29,996,224,275,833.
The number 2099 has only two factors, 1 and 2099, so it meets the definition of a prime number.
The sum of all the factors of 1000 is 2 4 − 1 2 − 1 × 5 4 − 1 5 − 1 = 2340 \frac{ 2^4 - 1 } { 2 - 1 } \times \frac{ 5^ 4 - 1 } { 5-1 } = 2340 2−124−1×5−154−1=2340.
Answer: The sum of the series 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 is equal to 45.
The prime factors of 63 are 3 and 7. Therefore, the sum is 3 + 7 = 10.