A leap year has 366 days or 52 weeks and 2 odd days. The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}. So there are 7possibilities out of which 2 have a Sunday. So the probability of 53 Sundays is 2/7.
Therefore, the probability of only 52 Sundays in a Leap year is 75. Was this answer helpful?
In a leap year there will be 52 Mondays and 2 days will be left. Of these total 7 outcomes, the favourable outcomes are 2. Hence the probability of getting 53 Mondays in a leap year is 27.
Hence, the probability that a leap year has 53 Fridays or 53 Saturdays is 37.
Detailed Solution
So the probability of 53 Saturday is 2/7. Hence, the correct answer is 2/7.
The probability that a non leap year will have 53 Fridays and 53 Satur... Therefore, Total possibility is zero.
So, Probability that a non leap yeas has 53 Fridays=TotalnumberofoutcomesNumberoffavourableoutcomes=71.
Answer: The probability of getting 53 Sundays in a non-leap year is 1/7.
Hence the probability of getting 53 Tuesdays in an ordinary year is =71.
Therefore the required probability is 73.
There are 366 days in a leap year, i.e, 1 more than a normal year. That means that we already have 52 sundays for sure. Then, we are left with 2 days. Now, these days can be any from a pair of- mon-tues,tues-wed,wed-thurs,thurs-fri,fri-sat,sat-sun,sun-mon.
Hence, required probability = 72.
Answer. Probability of having 50 Sundays in a non-leap year is 1. Its because each year we have 52 weeks and each week contains one Sunday. Therefore every year we have 52 Sundays and thus this is a sure event and its probability is 1.
6/7 or 0.86 is probability for 52 Mondays in a non-leap year.
An ordinary year has 365 days consisting of 52 weeks and 1 day. This day can be any day of the week. Therefore, P(of this days to be Monday) = 17 . Thus, the probability that an ordinary year has 53 Mondays is 17 .
What is the probability having 53 Thursdays in ordinary year (except leap year)? (1) 2 / 7.
The rule is that if the year is divisible by 100 and not divisible by 400, leap year is skipped. The year 2000 was a leap year, for example, but the years 1700, 1800, and 1900 were not. The next time a leap year will be skipped is the year 2100.
Expert-Verified Answer
We have to find probability of Saturday being there in a week. Total number of Saturdays in a week = 1. The possible number of Saturdays in a week = 1. Therefore, the probability of getting a Saturday in a week = (1/1) = 1.
The probability of a sure event is always 1.
there can be 53 sundays in a leap year if that one extra day is a sunday. Therefore, the maximum number of sundays in an random year is 53. There is no way a leap year can have 54 sundays.
Hence the probability of 53 Tuesdays =27.
Thus probability of having 53 Mondays in a leap year =72. Was this answer helpful?
A leap year. We know a leap year consists of 366 days. That makes up for$\dfrac{{366}}{7}$= 52 weeks + 2 days. It is obvious that there are 52 Tuesdays in those 52 weeks, therefore the probability that the leap year has 53 Tuesdays is the probability that the remaining two days will be Tuesdays.
About Those Leap Year Babies
28 or March 1. According to History.com, about 4.1 million people around the world have been born on Feb. 29, and the chances of having a leap birthday are one in 1,461.
In a non-leap year, there are 365 days i.e, 52 weeks and 1 odd day. So, there are 52 Tuesdays and if the 1 odd day is Tuesday so it is possible that there are 53 Tuesdays in a non-leap year.